Web27 de jan. de 2024 · For each operation * defined below, determine whether * is binary, commutative or associative. (i) On Z, define a*b = a-b (ii) On Q, define a*b = ab + asked Nov 13, 2024 in Sets, Relations and Functions by KanikaSharma (92.1k points) class-12; relations-and-functions; 0 votes. 1 answer WebOn Z+, define * by a * b = c where c is the smallest integer greater than both a and b. Does it give a binary operation? Please refer to this answer, and ignore the part where I talk about [math]x [/math] and [math]y [/math]: Also, there’s a surprisingly large number of related homework problems here on Quora: Continue Reading 9 1 4
On Z+, define * by a * b = c where c is the largest integer ... - Quora
Web25 de mar. de 2024 · Define * on Z by a * b = a + b - ab. Show that * is a binary operation on Z which is commutative as well as associative. binary operations class-12 Share It On 1 Answer +1 vote answered Mar 25, 2024 by Badiah (28.5k points) selected Mar 25, 2024 by Ekaa Best answer * is an operation as a*b = a+ b - ab where a, b ∈ Z. WebClick here👆to get an answer to your question ️ Let ∗ be a binary operation on Z defined by a∗ b = a + b - 4 for all a,b∈ Z .Show that '∗ ' is commutative. Solve Study Textbooks Guides. Join / Login >> Class 12 >> Maths >> Relations and Functions >> Binary Operations >> Let ∗ be a binary operation on Z define. can bottle recycle center
defined below, determine whether * is comm - teachoo
WebOn Z+, define * by a * b = c where c is the smallest integer greater than both a and b. Does it give a binary operation? Ad by JetBrains Write better C++ code with less effort. Boost your efficiency with refactorings, code analysis, unit test support, and an integrated debugger. Download All related (35) Sort Recommended Mitchell Schoenbrun Web22 de mar. de 2024 · (i) On Z+, define * by a * b = a − b Given a * b = a − b. Here, a ∈ Z+ & b ∈ Z+ i.e. a & b are positive integers Let a = 2, b = 5 2 * 5 = 2 – 5 = –3 But –3 is not a … WebAnswer (1 of 3): It is not because a binary operation on a set takes two elements of that set and produces an element of that set as well. This operation fails to do that in the case … can bottle return